hamzie
First Class Captain
- Joined
- Feb 10, 2010
- Runs
- 5,000
Yuck. It's boooring and sucks.
Never
its amazing!
Medicineeeee for lifeeeeeeeeeeeeeeeeeeeeeeee
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Yuck. It's boooring and sucks.
Never call the slope, "gradient".
slope = gradient, but slope is the proper word.
Its fine, unless you want to go in details.
In terms of ranking;
1) Slope
2) gradient
3) incline
Major what kind of a formulae was that :s To work out the area of a triangle you just do half of (base x height).
What is 2+4?
Or the number of ODIs Ireland has won against Test nations.![]()
Or 1/2abSinC, when it's not a right angled triangle.
I think you are right.
No, it was BL.96* is that you yh helping people with their hw B)
And yh that sounds right.
You need to mention more detail, as in you need to measure length, width and the height of the book and multiply these 3 to get the volume. You can't get the volume off the ruler straight.![]()
How is a mineral different from an ore?
I don't have it in my textbook and I can't find a suitable answer on internet.
[MENTION=134963]96NotOut[/MENTION], [MENTION=135402]cricket083[/MENTION], [MENTION=131701]Mamoon[/MENTION], [MENTION=14431]blinding light[/MENTION] and [MENTION=39010]Munna[/MENTION], please help. Any help will be appreciated.
Its different. Very different![]()
How is a mineral different from an ore?
I don't have it in my textbook and I can't find a suitable answer on internet.
[MENTION=134963]96NotOut[/MENTION], [MENTION=135402]cricket083[/MENTION], [MENTION=131701]Mamoon[/MENTION], [MENTION=14431]blinding light[/MENTION] and [MENTION=39010]Munna[/MENTION], please help. Any help will be appreciated.
Ok let's try again...
Minerals are naturally occurring substances present in the earth's crust. And what I remember from my miserable chemistry days, it will have a fixed definite chemical formula. In even more simpler terms, it means it will have the same substance throughout and not like a rock which may have different combination of elements/metals/minerals.
Ore is basically a mineral or an aggregate of minerals from which a valuable constituent, especially a metal, can be profitably mined or extracted. So for your easy understanding, you can assume ore is a business end product extracted from minerals. So if I'm a businessman, then I would go: Jab bhi koi mineral dekhun, mera dil deewana bole ore ore ore... ore ore ore![]()
Does anybody know the code you have to type to get this output? I have been stuck on this for a while...if you can help you would really save me (PS output of the code should look exactly like the one below)
Enter Quiz #1 ===>> 87
Enter Quiz #2 ===>> 92
Enter Homework #1 ===>> 100
Enter Homework #2 ===>> 93
Enter Homework #3 ===>> 98
Enter Homework #4 ===>> 88
Enter Homework #5 ===>> 100
Enter Test #1 ===>> 90
Enter Test #2 ===>> 87
Enter Test #3 ===>> 92
Enter your name ==>> Bob Jones
Bob Jone’s grades
Quiz Grades --> 87, 92
Homework Grades-->100, 93, 98, 88, 100
Test Grades --> 90, 87, 92
Quiz Average Home work Average Test Average Nine weeks average
----------------- -------------------------- ----------------- ------------------------
89.50 95.80 89.67 91
#include <iostream>
#include <cmath>
using namespace std;
string name;
int quiz1;
int quiz2;
int homework1;
int homework2;
int homework3;
int homework4;
int homework5;
int test1;
int test2;
int test3;
double quizAverage;
double homeworkAverage;
double testAverage;
double finalAverage;
int main()
{
cout << "Enter Quiz #1 ===>> ";
cin >> quiz1;
cout << "Enter Quiz #2 ===>> ";
cin >> quiz2;
cout << "Enter Homework #1 ===>> ";
cin >> homework1;
cout << "Enter Homework #2 ===>> ";
cin >> homework2;
cout << "Enter Homework #3 ===>> ";
cin >> homework3;
cout << "Enter Homework #4 ===>> ";
cin >> homework4;
cout << "Enter Homework #5 ===>> ";
cin >> homework5;
cout << "Enter Test #1 ===>> ";
cin >> test1;
cout << "Enter Test #2 ===>> ";
cin >> test2;
cout << "Enter Test #3 ===>> ";
cin >> test3;
cout << "Enter your name ===>> ";
cin >> name;
quizAverage = (quiz1 + quiz2) / 2;
homeworkAverage = (homework1 + homework2 + homework3 + homework4 + homework5) / 5;
testAverage = (test1 + test2 + test3) / 3;
finalAverage = quizAverage * 0.3 + homeworkAverage * 0.2 + testAverage * 0.5;
cout << name << "'s grades" << endl;
cout << "Quiz Grades --> " << quiz1 << ", " << quiz2 << endl;
cout << "Homework Grades --> " << homework1 << ", " << homework2 << ", " << homework3 << ", " << homework4 << ", " << homework5 << endl;
cout << "Test Grades --> " << test1 << ", " << test2 << ", " << test3 << endl;
cout << "Quiz Average: " << quizAverage << endl;
cout << "Home work Average: " << homeworkAverage << endl;
cout << "Test Average: " << testAverage << endl;
cout << "Nine weeks average: " << finalAverage << endl;
}
Code:#include <iostream> #include <cmath> using namespace std; string name; int quiz1; int quiz2; int homework1; int homework2; int homework3; int homework4; int homework5; int test1; int test2; int test3; double quizAverage; double homeworkAverage; double testAverage; double finalAverage; int main() { cout << "Enter Quiz #1 ===>> "; cin >> quiz1; cout << "Enter Quiz #2 ===>> "; cin >> quiz2; cout << "Enter Homework #1 ===>> "; cin >> homework1; cout << "Enter Homework #2 ===>> "; cin >> homework2; cout << "Enter Homework #3 ===>> "; cin >> homework3; cout << "Enter Homework #4 ===>> "; cin >> homework4; cout << "Enter Homework #5 ===>> "; cin >> homework5; cout << "Enter Test #1 ===>> "; cin >> test1; cout << "Enter Test #2 ===>> "; cin >> test2; cout << "Enter Test #3 ===>> "; cin >> test3; cout << "Enter your name ===>> "; cin >> name; quizAverage = (quiz1 + quiz2) / 2; homeworkAverage = (homework1 + homework2 + homework3 + homework4 + homework5) / 5; testAverage = (test1 + test2 + test3) / 3; finalAverage = quizAverage * 0.3 + homeworkAverage * 0.2 + testAverage * 0.5; cout << name << "'s grades" << endl; cout << "Quiz Grades --> " << quiz1 << ", " << quiz2 << endl; cout << "Homework Grades --> " << homework1 << ", " << homework2 << ", " << homework3 << ", " << homework4 << ", " << homework5 << endl; cout << "Test Grades --> " << test1 << ", " << test2 << ", " << test3 << endl; cout << "Quiz Average: " << quizAverage << endl; cout << "Home work Average: " << homeworkAverage << endl; cout << "Test Average: " << testAverage << endl; cout << "Nine weeks average: " << finalAverage << endl; }
The only thing that needs to be done is formatting the output at the end and the precision of the numbers (how many digits). Sorry I had to leave, let me know if you still can't get that.
Would this also work c++ language?Code:#include <iostream> #include <cmath> using namespace std; string name; int quiz1; int quiz2; int homework1; int homework2; int homework3; int homework4; int homework5; int test1; int test2; int test3; double quizAverage; double homeworkAverage; double testAverage; double finalAverage; int main() { cout << "Enter Quiz #1 ===>> "; cin >> quiz1; cout << "Enter Quiz #2 ===>> "; cin >> quiz2; cout << "Enter Homework #1 ===>> "; cin >> homework1; cout << "Enter Homework #2 ===>> "; cin >> homework2; cout << "Enter Homework #3 ===>> "; cin >> homework3; cout << "Enter Homework #4 ===>> "; cin >> homework4; cout << "Enter Homework #5 ===>> "; cin >> homework5; cout << "Enter Test #1 ===>> "; cin >> test1; cout << "Enter Test #2 ===>> "; cin >> test2; cout << "Enter Test #3 ===>> "; cin >> test3; cout << "Enter your name ===>> "; cin >> name; quizAverage = (quiz1 + quiz2) / 2; homeworkAverage = (homework1 + homework2 + homework3 + homework4 + homework5) / 5; testAverage = (test1 + test2 + test3) / 3; finalAverage = quizAverage * 0.3 + homeworkAverage * 0.2 + testAverage * 0.5; cout << name << "'s grades" << endl; cout << "Quiz Grades --> " << quiz1 << ", " << quiz2 << endl; cout << "Homework Grades --> " << homework1 << ", " << homework2 << ", " << homework3 << ", " << homework4 << ", " << homework5 << endl; cout << "Test Grades --> " << test1 << ", " << test2 << ", " << test3 << endl; cout << "Quiz Average: " << quizAverage << endl; cout << "Home work Average: " << homeworkAverage << endl; cout << "Test Average: " << testAverage << endl; cout << "Nine weeks average: " << finalAverage << endl; }
The only thing that needs to be done is formatting the output at the end and the precision of the numbers (how many digits). Sorry I had to leave, let me know if you still can't get that.
Ok let's try again...
Minerals are naturally occurring substances present in the earth's crust. And what I remember from my miserable chemistry days, it will have a fixed definite chemical formula. In even more simpler terms, it means it will have the same substance throughout and not like a rock which may have different combination of elements/metals/minerals.
Ore is basically a mineral or an aggregate of minerals from which a valuable constituent, especially a metal, can be profitably mined or extracted. So for your easy understanding, you can assume ore is a business end product extracted from minerals. So if I'm a businessman, then I would go: Jab bhi koi mineral dekhun, mera dil deewana bole ore ore ore... ore ore ore![]()
Would this also work c++ language?
And if so I'd like to thank you for helping me I was stuck on this for a while because I couldn't remember this from a year or two back for some reason
Sent from my SM-G900T using Tapatalk
OK got it thank uIt is in C++.
I need a sad song for a presentation. Presentation is on drinking and driving. Any suggestions?
I need a sad song for a presentation. Presentation is on drinking and driving. Any suggestions?
Okay guys I need help in Microeconomics (yet another stupid core eco course for my degree).
It's pretty basic stuff, but I'm a dumb dodo when it comes to math and eco.
Inverse demand curve is => p = 1000 − 4QD(p)
Inverse supply curve is => p = 50 + QS(p)
Solve for equilibirum.
I know we solve by putting them equal to each other, get the equilibrium quantity, plug it into the function again, and get the equilibrium price.
But what the hell are those 4Qd(p) and Qs(p) stuff? Do I take this (p) to the other side and square it? God, I hate this. Please help. I want to punch myself.
Okay guys I need help in Microeconomics (yet another stupid core eco course for my degree).
It's pretty basic stuff, but I'm a dumb dodo when it comes to math and eco.
Inverse demand curve is => p = 1000 − 4QD(p)
Inverse supply curve is => p = 50 + QS(p)
Solve for equilibirum.
I know we solve by putting them equal to each other, get the equilibrium quantity, plug it into the function again, and get the equilibrium price.
But what the hell are those 4Qd(p) and Qs(p) stuff? Do I take this (p) to the other side and square it? God, I hate this. Please help. I want to punch myself.
Is this a trick question cuz honestly it looks too simple so I'm baffled as to why you're struggling.
It's been a good five or so years since I was taking an micro course though so maybe I'm just missing out on sth
I don't know anything about economics, but the QD(p) and QS(p) are probably Demand and Supply of p. So when p appears inside parentheses, it indicates the usage of p in the Demand and Supply functions, and you wouldn't use (p) in any mathematical operation, like taking it to the other side and squaring it.
The 4 next to the QD(p) in the first equation is a product though, so 4QD(p) is 4 times QD(p).
So if p = 1000 - 4DQ(p) and p = 50 + QS(p), then
1000 - 4DQ(p) = 50 + QS(p), so
950 = QS(p) + 4DQ(p)
I wouldn't know what to do beyond this.
I get the same Nostalgic, bro. I just don't know if it's right.
Undergrad was good. Masters suck. Economics suck. I hate it. I hate it. I wanna go back.. *goes in a corner and cries*
Is there any other pertinent information in the question? It seems like with the two equations, you're left with a relation that wouldn't allow you to solve for either QS(p) or QD(p) or p for that matter. I would think the functions QS() and QP() would be provided.
Nope, nothing else required for this part.
We're solving for equilibrium. That's where demand and supply intersect, and become equal, so we assume QD = QS.
So assuming QD = QS = QE (quantity at equilibrium), we put the two equations equal to each other.
I'm sorry I'm bugging you with this at this hour.. It's been a really tough past few weeks.
Oh, so if QD = QS, that's a third equation. So if,
950 = QS(p) + 4QD(p), and
QS(p) = QD(p), then
950 = 5QD(p), and
QD(p) = QS(p) = 190
and if we plug that into either of the first two equations, p = 240
But I guess you're concerned that this seems too easy... maybe it isn't, and those really are the answers?
Yep, yep and yep...
Yesssssss! I just don't want to lose any marks over something as stupid as this![]()
Guys its an Inverse demand function
its slightly different from the normal demand and supply from what i recall
so you cant do Qd = Qs
just have a refresher on that and youll be fine
i havent done this myself in eons and have a ton of other work to do so sorry cant be of direct help atm as i dont wanna give you a wrong answer but dont follow Nostalgics calculation lol where Qd=Qs
But she told me QS(p)=QD(s)...![]()
actually youre right then
formulas are just rearranged for p than the Q(d) and Q(s) as in normally
actually youre right then
formulas are just rearranged for p than the Q(d) and Q(s) as in normally
though then again it seems too simple because im assuming its not introductory level if shes in masters
haha im stumped honestly. though for this purpose ill just cut out and go with the working above
Guys its an Inverse demand function
its slightly different from the normal demand and supply from what i recall
so you cant do Qd = Qs
just have a refresher on that and youll be fine
i havent done this myself in eons and have a ton of other work to do so sorry cant be of direct help atm as i dont wanna give you a wrong answer but dont follow Nostalgics calculation lol where Qd=Qs
Nostalgic said:I'd be very interested in finding out if this really was the solution, or if there was a catch all along. When do you find out? I'll be waiting on tenterhooks, so emotionally invested am I in this problem now.
It is introductory level Micro! My Masters program is in International Relations, not Economics - and most people are studying this for the first time! Hence the basic introductory course --
I totally get the whole inverse demand thing. Inverse demand function basically makes price the subject. All I wanted to know was that since the question SAYS that the inverse demand function is => p = 1000 - 4QD(p), what the )**&@^$@_ hell that stupid (p) next to 4QD means here..
And if that dang thing is calculus or not!![]()
![]()
I've asked some people. Let's see what they get. Meanwhile, I'll just go bang my head on the book again4 more pages of problem sums to go - weee
Don't worry.. It's as good as any.. Thanks still tho.
Next week! This is due Monday
Thanks still for all your help - although I gotta wonder how come your life became so boring as to worry about an econ problem like that - one you don't even have to submit?
Dang. I missed these smileys![]()
As far as I know, there shouldn't be any Calculus involved. My younger brother's doing micro and he hasn't even learned Pre-cal let alone Calculus. Have you tried WikiAnswers? Like copy paste the question in Google's search engine? lol.
There's supposedly calculus involved at some point but man, I don't even know.. I honestly just hope I pass (after a whirlwind of craziness in undergrad, I'm done stressing over grades.)
I tried that. Nada :/
Have you learned Calculus at all? Pretty unfair to be asking you to use it if you didn't.
Hey [MENTION=14431]blinding light[/MENTION], this should help you out.
Nope :/
It's a pass/fail thing tho. Let's see how it goes.
Thanks I already knew that
Most people I know are solving it exactly as how Nostalgic and I did it here.. so I'm sticking with that![]()
Okay guys I need help in Microeconomics (yet another stupid core eco course for my degree).
It's pretty basic stuff, but I'm a dumb dodo when it comes to math and eco.
Inverse demand curve is => p = 1000 − 4QD(p)
Inverse supply curve is => p = 50 + QS(p)
Solve for equilibirum.
I know we solve by putting them equal to each other, get the equilibrium quantity, plug it into the function again, and get the equilibrium price.
But what the hell are those 4Qd(p) and Qs(p) stuff? Do I take this (p) to the other side and square it? God, I hate this. Please help. I want to punch myself.